One number is 4 less than three times another number if their sum is increased by 5 the result is 25 find both the number
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btq ,
x=3y-4_____(1)
x+y+5=25______(2)
now,
substituting the value of x in eq(2),we get
4-3y+y+5=25
9-2y=25
-2y=25-9
=16
y=-8
now,substituting the value of y in eq(1),we get
x=4-3*(-8)
=4+24
=28
therefore,
x=28
y=-8
x=3y-4_____(1)
x+y+5=25______(2)
now,
substituting the value of x in eq(2),we get
4-3y+y+5=25
9-2y=25
-2y=25-9
=16
y=-8
now,substituting the value of y in eq(1),we get
x=4-3*(-8)
=4+24
=28
therefore,
x=28
y=-8
Anonymous:
i like maths lovers .... keep going and growing.....have a nyc future ahead.
thc
I meant thx
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