Question

One number is 6 more than the other number.Also 7 times the smaller number equal to 6 times the larger number .find the two numbers??

Answer 1

Answer:

$Required \:two \: numbers \: are ,\\smaller \: number = 36\\Larger \: number = x+6 = 42$

Step-by-step explanation:

$Let \: smaller \: number \:be \:x$

$Larger \:number = x+6$

/* According to the problem given,

7 times the smaller number equal to 6 times the larger number

$7x = 6(x+6)$

$\implies 7x = 6x + 36$

$\implies 7x-6x = 36$

$\implies x = 36$

Therefore,

$Required \:two \: numbers \: are ,\\smaller \: number = x = 36\\Larger \: number = x+6 = 36+6 = 42$

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Answer 2

Answer:

the number is 4

Step-by-step explanation:

x+x/2=6

(2x+x)/2=6

3x/2=6

3x=6×2

3x=12

x=12/3=4