Question

One number is 7 more than another and it's square is 77 more than than the smaller number .Find the numbers
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Answer 1

Answer:

Numbers are - 2 and 9

Step-by-step explanation:

let the no. be = x

second no.be = x+7

According to the question

{x + 7}^{2} = 77 + {x}^{2}

{x}^{2} + 49 + 14x = 77 + {x}^{2}

{x}^{2} - {x}^{2} + 14x = 77 - 49

14x = 28

x = 28 / 14

x = 2

x + 7 = 9

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Answer 2

let one number be x

other no =x+7

(x+7)² -77 =x²

x²+49+14x-77=x²

x²-28+14x=x²

x²-x²+14x = 28

14x= 28

x= 2

other no = x+7 =2+7 =9

the numbers are 2 and 9

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