Math, asked by ironmanual10, 10 months ago

Simplify if you are a Math God

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Answered by Anonymous

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$\frac{7 \sqrt{3} }{ \sqrt{10} + \sqrt{3} } - \frac{2 \sqrt{5} }{ \sqrt{6} + \sqrt{5} } - \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2} } \\ \\ \frac{7 \sqrt{3} }{ \sqrt{10} + \sqrt{3} } \times \frac{ \sqrt{10} - \sqrt{3} }{\sqrt{10} - \sqrt{3} } = \\ \\ \frac{7 \sqrt{3} (\sqrt{10} - \sqrt{3}) }{(\sqrt{10} + \sqrt{3})( \sqrt{10} - \sqrt{3} ) } \\ \\ \frac{7 \sqrt{3} (\sqrt{10} - \sqrt{3}) }{10 - 3 } \\ \\ \frac{7 \sqrt{3}( \sqrt{10} - \sqrt{3} )}{7} \\ \sqrt{3 } (\sqrt{10} - \sqrt{3)} \\ \\ \\ \frac{2 \sqrt{5} }{ \sqrt{6} + \sqrt{5} } \ \\ \\ \ \frac{2 \sqrt{5} }{ \sqrt{6} + \sqrt{5} } \times \frac{ \sqrt{6 } - \sqrt{5}}{\sqrt{6 } - \sqrt{5}} \\ \\ \frac{2 \sqrt{5}( \sqrt{6} - \sqrt{5} )}{( \sqrt{6 } + \sqrt{5} )( \sqrt{6} - \sqrt{5} ) } \\ \\ \frac{2 \sqrt{5}( \sqrt{6} - \sqrt{5)} }{1} \\ \\ \\ \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2} } \\ \\ \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2} } \times \frac{\sqrt{15} - 3 \sqrt{2} }{\sqrt{15} - 3 \sqrt{2} } \\ \\ \frac{3 \sqrt{2}(\sqrt{15} - 3 \sqrt{2}) }{(\sqrt{15} + 3 \sqrt{2} )(\sqrt{15} - 3 \sqrt{2} )} \\ \\ \frac{3 \sqrt{2}(\sqrt{15} - 3 \sqrt{2} ) }{15 - 18} \\ \\ \frac{3 \sqrt{2} (\sqrt{15} - 3 \sqrt{2} )}{ - 3} \\ \\ - \sqrt{2} (\sqrt{15} - 3 \sqrt{2} ) \\ \\ now \: putting \: all \: the \: values \\ \\ \: \sqrt{3} ( \sqrt{10} - \sqrt{3} ) - 2 \sqrt{5} ( \sqrt{6} \\ - \sqrt{5} ) - ( - \sqrt{2} ( \sqrt{15} - 3 \sqrt{2} )$

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Simplify if you are a Math God