Question

one number is 7 more than another and it's square is 77 more than square of the smaller number . What are the numbers​

Answer 1

Answer:

2 and 9

Given:

Let the one number be X

and other number be X+7

Solution:

Let x = the smaller number

Let x + 7 = the larger number

(x + 7)^2 = x^2 + 77

x^2 + 14x + 49 = x^2 + 77

14x = 28

x = 2

x + 7 = 9

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Answer 2

let one number be x

other no =x+7

(x+7)² -77 =x²

x²+49+14x-77=x²

x²-28+14x=x²

x²-x²+14x = 28

14x= 28

x= 2

other no = x+7 =2+7 =9

the numbers are 2 and 9

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