Question

one number is 7 more than another and its square is 77 more than the square of the smaller number.What are the number?​

Answer 1

Answer:

9 & 2

Step-by-step explanation:

Let the numbers be "x" and "y" respectively

Then,

x = 7 + y

x - y = 7 .....(1)

and,

x² = 77 + y²

x² - y² = 77

(x + y)(x - y) = 77

From equation (1)

(x + y)7 = 77

x + y = 77/7

x + y = 11 .....(2)

Add equations (1) and (2)

x - y + x + y = 7 + 11

2x = 18

x = 18/2

x = 9

If x = 9 then from equation (1)

x - y = 7

y = x - 7

y = 9 - 7

y = 2

Answer 2

Answer:

2 & 9

Step-by-step explanation:

Let one number be x

other no =x+7

(x+7)² -77 =x²

x²+49+14x-77=x²

x²-28+14x=x²

x²-x²+14x = 28

14x= 28

x= 2

other no = x+7 =2+7 =9

the numbers are 2 and 9

I hope this would help you mate

Thanks for asking and keep asking more