one number is 7 more than another and its square is 77 more than square of the smaller number. what are the numbers
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Answered by
15
let one no be x-7
then another no . be x
x2=(x-7)^2+77
x2=x2+49-14x+77
-14x+126=0
14x=126
x=126/14
x=9
x-7=2
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so two digits are 9 and 2
Answered by
14
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