a stone thrown vertically up reaches the maximum height in 3sec .if the acceleration of the stone be 9.8m/sec^2.calculate its initial velocity
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v=u+at
o=u+(-9.8)(3
u=9.8×3
=29.4m/s
o=u+(-9.8)(3
u=9.8×3
=29.4m/s
siliverisrinivas:
is my answer correct
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