Question

One number is 7 times another. If their difference is 18, find the numbers​

Answer 1

Let smaller number be x.

Let bigger number be y.

Then, according to the question,

y=7x

And,

y-x=18

Substitute the value of y here.

7x-x=18

6x=18

x=3

Substitute value of x in y=7x

y=7×3

y=21

Numbers: 3 and 21

Answer 2

Given:

✰ One number is 7 times another.

✰ The difference between two number is 18.

To find:

✠ The numbers.

Solution:

Lets understand the concept first! First we will assume the both numbers as x and y respectively. Then, we know that the one number is 7 times another that means 7 will be multiplied by another number is equal to one number. We also know that the difference between two number is 18. Thus, forming an adequate equation and doing required calculations, we will find both the numbers.

Let's find out...✧

Let the numbers be x and y respectively.

⇾One number is 7 times another.

⇾x = 7y

According to the question,

➤ x - y = 18

Substitute the value of x in the above expression, we have:

➤ 7y - y = 18

➤ 6y = 18

➤ y = 18/6

➤ y = 3

Now, find out the another number.

➤ x = 7y

➤ x = 7 × 3

➤ x = 21

∴ Both the numbers are 3 and 21 respectively.

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