one number is 7 times another. if their difference is 18, find the numbers
Answers
Answered by
25
Answer:
Step-by-step explanation:
- x = one number
- y = another
- x = 7y
- x-y =18
.
substitute x=7y
- 7y-y = 18
- 6y = 18
- y = 3
.
substitute y=3
- x = 7y
- x = 7(3)
- x = 21
.
Always check your answer.
Is the difference = 18?
21 -3 = 18.
Correct.
And of course, we know 21 = 3×7
.
The two numbers are 3 and 21.
.
Done
Hope it Helps!
Answered by
5
Answer:
*let the number greater than other number by seven times be x, other number be y
i.e
x=7y-------1
*given difference between the numbers is 18
x-y =18------2
*substitute the value of x in equation 2
7y-y=18
6y=18
y=3
*substitute the value of y in equation 1
x=7(3)
x=21
therefore the numbers are 3 and 21
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