Math, asked by XxsinglequeenxX28, 1 day ago

one number is 7 times another. if their difference is 18, find the numbers​

Answers

Answered by Anonymous
25

Answer:

{\huge\textbf{\textsf{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}}}} }

Step-by-step explanation:

  • x = one number
  • y = another
  • x = 7y
  • x-y =18

.

substitute x=7y

  • 7y-y = 18

  • 6y = 18
  • y = 3

.

substitute y=3

  • x = 7y
  • x = 7(3)
  • x = 21

.

Always check your answer.

Is the difference = 18?

21 -3 = 18.

Correct.

And of course, we know 21 = 3×7

.

The two numbers are 3 and 21.

.

Done

Hope it Helps!

Answered by nikhilsram2004
5

Answer:

*let the number greater than other number by seven times be x, other number be y

i.e

x=7y-------1

*given difference between the numbers is 18

x-y =18------2

*substitute the value of x in equation 2

7y-y=18

6y=18

y=3

*substitute the value of y in equation 1

x=7(3)

x=21

therefore the numbers are 3 and 21

Similar questions
English, 1 day ago