One number is four less than three times another.
If their sum is increased lys, the result is 25. find the numbers
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Let the numbers be x and y respectively.
Now, According to the question:
One number is four less than three times another i.e, y=3x - 4(Let x is a smaller number than y).
Initial Sum: old sum = x+y
Now, sum is increased by 5 i.e, new sum = old sum + 5 = 25
So, new sum = 25 and old sum = 20.
Thus, we get two equations as: 3x - 4 =y (1st equation)
y = 20 - x (2nd equation)
Now, subtract equation2 from equation 1 we get:
(3x - 4) - (20 - x ) =y- y
3x - 4 -20 +x =0
4x - 24 =0
4x = 24
x = 6
Putting value of x in equation 2 , we get:
y = 20 - 6
y = 14
Hence, value of x and y are 6 and 14 respectively or 14 and 6 depending upon
which number you choosen smaller.
If, x>y then, x= 14 and y=6
otherwise then, x=6 and y=14
hope u understand
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