one number is selected from first 30 positive integers. What is the probability that it is divisible by 3 or 5?
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Step-by-step explanation:
total no. of events = 30
numbers divisible by 3 are 3,6,9,12,15,18,21,24,27,30 a total no. of 10 numbers
numbers divisible by 5 are 5,10,15,20,25,30 a total no. of 6 numbers
no. of numbers divisible by 3 or 5 are [ (10+6)-2 ] = 14 {since 15,30 comes twice}
HENCE probability is = 14/30 = 0.466667
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