Question

One number is Seven times another. If their difference is 18,find the numbers

Answer 1

Answer:

THE NUMBERS WERE 21 AND 3

Step-by-step explanation:

LET THE SMALLER NUMBER BE X

BIGGER NUMBER = 7 X

ACCORDING TO THE QUESTION , 7 X - X = 18

= 6 X = 18

X = 3 ;

SO, THE SMALLEST NUMBER = 3 ;

AND THE BIGGER NUMBER =

7 * 3 = 21;

SO , THE BIGGER NUMBER = 21 ;

                           VERIFICATION                                                                            

THE SMALLEST NUMBER WAS 3

AND THE BIGGER NUMBER WAS 21

21 - 3 = 18 ;

SINCE IN THE QUESTION, IT WAS GIVEN THAT THEIR DIFFERENCE IS 18 ,

SO R.H.S = L.H.S = 18.

HENCE PROVED .

THE NUMBERS WERE 21 AND 3.

THANK YOU . NICE DAY

MAY SUCCESS BE ALWAYS WITH YOU  AND PLEASE MARK AS BRAINLIEST.

Answer 2

ɢɪᴠᴇɴ :

1. one number is seven times the other.
2. Their difference is 18.

ᴛᴏ ғɪɴᴅ :

• Find the number.

sᴏʟᴜᴛɪᴏɴ :

Here, we are given with statement only and we need to make a linear equation out of it, and then solve the problem. First we will take the no: as x and then second as 7x, then by transpose method, we will solve it further.

sᴏ -

Let the number be termed as x

One is seven times the other number = 7x

Difference is of 18

ᴏɴ sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs :

⟶ 7x - x = 18

⟶ 6x = 18

$⟶ x = \sf\cancel\dfrac{18}{6}$

⟶ x = 3

ɴᴏᴡ :

• First number = 3

• Second number = 7x = 7 × 3 = 21

ᴠᴇʀɪғɪᴄᴀᴛɪᴏɴ :

21 - 3 = 18

18 = 18

\therefore∴ The first and second number are 3 and 21

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