Question

one number is seven times another if their difference is 18.find the number​

Answer 1

• GIVEN:-

1. one number is seven times another.
2. Their difference is 18.

• To Find:-

The numbers.

• SOLUTION:-

Let the two nos be x and 7x.

Their difference = 18

According to the question,

$\large\Longrightarrow{\sf{7x-x=18}}$

$\large\Longrightarrow{\sf{6x=18}}$

$\large\Longrightarrow{\sf{x=\dfrac{18}{6}}}$

$\large\Longrightarrow{\sf{x=\dfrac{\cancel{18}\:\:\:\:3}{\cancel{6}}}}$

$\large\therefore\boxed{\sf{x=3}}$

The numbers are;-

1. x = 3
2. 7x = 7 × 3 = 21

• Now let's verify it:-

$\large\Longrightarrow{\sf{21-3=18}}$

$\large\Longrightarrow{\sf{18=18}}$

$\large\therefore\boxed{\sf{LHS=RHS}}$

$\large\red\therefore\boxed{\sf{\red{The\:numbers\:are\:3\:and\:21.}}}$

Answer 2

Given:

• One number is seven times the other number.
• Difference between the numbers is 18.

To find:

• The required numbers.

⠀⠀⠀⠀⠀⠀⠀

Solution:

Let the first number be "x".

And, the second number be "7x".

$\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}$

$:\implies\sf 7x - x = 18$

$:\implies\sf 6x = 18$

$:\implies\sf x = {\cancel {\dfrac{18}{6}}\:}^{3}$

$:\implies{\boxed{\frak{\pink{x=3}}}}\;\bigstar$

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The required numbers are :

• First number = x = 3
• Second number = 7x = 7×3 = 21

$\therefore\;{\underline{\sf{The \:required\:numbers\;are\; \bf{3\:and\;21\;}.}}}$⠀