Question

one numeber is seven times another. If their difference is find the number​

Answer 1

$\pink{ \huge{given}} \\ \\ x = 7y \\ x + y = 56\\ \\ \ \pink{ \huge{to \: \: find}} \\ \\ x \\ y \\ \\ \ \pink{ \huge{solution}} \\ \\ x = 7y \\ \\ x + y = 56 \\ \\ 7y + y = 56 \\ \\ \: \: \: \: \: \: \: \: 8y = 56 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: y = \frac{56}{8} \\ \\ \: \: \: \: \: \: \: \: \: \green{ \huge{y = 7} }\\ \\ x = 7y \\ \\ \: \: \: \: \: x = 7 \times 7 \\ \\ \blue{ \huge{x = 49}}$

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