Math, asked by samyukta135, 9 months ago

One of the acute angle in a right angled triangle is 60 and its adjacent side is 2root3. Find the area of triangle ​

Answers

Answered by ASHHD15
1

Step-by-step explanation:

IN TRIANGLE ABC

ANGLE C=60°

and it's adjacent side is 2√3

area of the triangle =1/2xbxh

base is 2√3

height =?

to find height we have to use trigonometry application

so,

TAN60=OPP/ADJ

TAN60°=h/2√3

√3=h/2√3

2√3*√3=h

2 * 3=h

h =6

so we got the height of the triangle

therefore, area of the triangle =1/2*b*h

=1/2*2√3*6

=6√3

therefore, the area of the triangle =6√3 units square

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Answered by adithyasellapillain
1

Answer:

tan 60°= AB / CB

√3= ab/2√3

√3x2√3=ab

ab = 2x3

= 6

area = ½bh

=½x2√3x6

=√3x6

6√3

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