One of the angle of the triangle is equal to the sum of other two angles. If the ratio of other two angles is 4:5.find the angles of the triangle.answer
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Let the Triangle be ABC
Given: ∠A= 4x ; ∠B= 56x ; ∠C= ∠A+∠B
∠C= 4x+5x= 9x
By Angle Sum Property
∠A+∠B+∠C= 180°
4x+5x+9x= 180°
18x= 180°
x= 180/18= 10°
∵ ∠A= 4x= 4(10)= 40°
∠B= 5x= 5(10)= 50°
∠C= 9x= 9(10)= 90°
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