One of the angles of a quadrilateral is thrice the smaller angle of a parallelogram the respective ratio between the adjacent angles of the parallelogram is 4 is to 5 remaining three angles of the quadrilateral are in the ratio 4 is to 11 is 29 respectively what is the sum of the largest and the smallest angles of the quadrilateral
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For the Parallelogram, 4x∘+5x∘=180∘4x∘+5x∘=180∘
=> 9x = 180 => x = 18091809 = 20
=> smaller angle of parallelogram = 4×204×20 = 80∘80∘
Therefore, One angle of the quadrilateral = 3×803×80 = 240∘240∘
Now. 4y + 11y + 9y
= 360 - 240 = 120
= 24y = 120 => y = 1202412024 = 5
=> Its smallest angle
= 4×54×5 = 20∘20∘
Therefore, Required sum = 240∘+20∘=260∘
For the Parallelogram, 4x∘+5x∘=180∘4x∘+5x∘=180∘
=> 9x = 180 => x = 18091809 = 20
=> smaller angle of parallelogram = 4×204×20 = 80∘80∘
Therefore, One angle of the quadrilateral = 3×803×80 = 240∘240∘
Now. 4y + 11y + 9y
= 360 - 240 = 120
= 24y = 120 => y = 1202412024 = 5
=> Its smallest angle
= 4×54×5 = 20∘20∘
Therefore, Required sum = 240∘+20∘=260∘
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