Math, asked by swaroopsathe8, 1 month ago

One of the angles of a rhombus with side 20cm is 60˚ ,then the lengths of the diagonals of this rhombus is__________ *
20 cm & 10 cm
20 cm & 20√3 cm
20√2 cm & 10√3 cm
10 cm & 10√3 cm​

Answers

Answered by Anonymous
116

Given :

  • One of the angles of a rhombus with side 20 cm is 60˚

To find :

The lengths of the diagonals of this rhombus.

Solution :

  • Properties of rhombus

★ All adjacent sides are equal

★ Diagonals are perpendicular bisector

★ Opposite sides are parallel

★ Opposite angles are equal

  • According to the given properties

AD = DC = CB = AB = 20cm

°•°∠BAD = 60°

•°• ∠BAE = ∠DAE = 30°

Now,

  • In ∆AED

→ sin 30° = DE/DA

→ 1/2 = DE/20

→ 2DE = 20

•°• DE = 20/2 = 10cm

  • Again in AED

→ cos 30° = AE/DA

→ √3/2 = AE/20

→ 20√3 = 2AE

→ AE = 20√3/2

•°• AE = 10√3cm

Length of diagonals of rhombus

→ AE = 10√3cm

AC = 2 × 103 = 203cm

→ DE = 10cm

DB = 2 × 10 = 20cm

•°• Length of diagonals are 203cm & 20cm

━━━━━━━━━━━━━━━━━━━━━━━━

Attachments:
Answered by Anonymous
54

Answer:

Given :-

  • One of the angles of a rhombus with side 20 cm is 60°.

To Find :-

  • What is the length of the diagonals of the rhombus.

Solution :-

\longmapsto In right angled triangle AED :

\sf sin 30^{\circ} =\: \dfrac{DE}{DA}

As we know that, [ sin 30° = ½ ]

\sf \dfrac{1}{2} =\: \dfrac{DE}{20}

By doing cross multiplication we get :

\sf 2(DE) =\: 20

\sf 2DE =\: 20

\sf DE =\: \dfrac{\cancel{20}}{\cancel{2}}

\sf\bold{\green{DE =\: 10\: cm}}

Now, again,

\longmapsto In right angled triangle AED :

\sf cos 30^{\circ} =\: \dfrac{AE}{DA}

As we know that, [cos 30° = 3/2 ]

\sf \dfrac{\sqrt{3}}{2} =\: \dfrac{AE}{20}

By doing cross multiplication we get :

\sf 2(AE) =\: 20\sqrt{3}

\sf 2AE =\: 20\sqrt{3}

\sf AE =\: \dfrac{\cancel{20}\sqrt{3}}{\cancel{2}}

\sf\bold{\green{AE =\: 10\sqrt{3}}}

Hence, the length of the diagonal are :

\sf DE =\: 10\: cm

\sf DB =\: 2 \times 10

\sf\bold{\red{DB =\: 20\: cm}}

And,

\sf AE =\: 10\sqrt{10}

\sf AC =\: 2 \times 10\sqrt{3}

\sf\bold{\red{AC =\: 20\sqrt{3}}}

\therefore The length of the rhombus is 20 cm and 203 cm.

Hence, the correct options is option no (2) 20 cm and 203 cm .

Similar questions
Math, 21 days ago