One of the angles of a triangle is 55 . Find the remaining two angles if their differnce is 35.
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Heya ......
Given :-
It is given that one angle is 55°. Also the difference between the remaining two sides are 35°.
So, x - y = 35°. .............(i)
We all know that the sum of angles of a triangle is 180°.
Let the other two angles be x and y.
ATQ,
55 + x + y = 180.
-> x + y = 180 - 55
-> x + y = 125. ........(ii)
Adding eq. (i) and (ii), we get
x + y = 125
x - y = 35
------------------------------------------------
2x = 160.
Hence, x = 80.
Putting x = 80 in eq. (i), we get
80 - y = 35.
-y = 35 - 80
y = 45.
Hence, the values of x and y are 80 and 45 respectively. So, the other two angles are 80° and 45°.
Let us verify ________
Sum of angles = 55° + 80° + 45° = 180°.
Hence, the sum of angles is 180°.
Also,
x - y = 80 - 45 = 35°.
Hence, Verified.........
Hope it helps............
Given :-
It is given that one angle is 55°. Also the difference between the remaining two sides are 35°.
So, x - y = 35°. .............(i)
We all know that the sum of angles of a triangle is 180°.
Let the other two angles be x and y.
ATQ,
55 + x + y = 180.
-> x + y = 180 - 55
-> x + y = 125. ........(ii)
Adding eq. (i) and (ii), we get
x + y = 125
x - y = 35
------------------------------------------------
2x = 160.
Hence, x = 80.
Putting x = 80 in eq. (i), we get
80 - y = 35.
-y = 35 - 80
y = 45.
Hence, the values of x and y are 80 and 45 respectively. So, the other two angles are 80° and 45°.
Let us verify ________
Sum of angles = 55° + 80° + 45° = 180°.
Hence, the sum of angles is 180°.
Also,
x - y = 80 - 45 = 35°.
Hence, Verified.........
Hope it helps............
RehanAhmadXLX:
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