Question

One of the angles of a triangle measures 80° and the other two angles are equal. Find the measure of each of the equal angles.

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Answer 1

$\rm\bf\underline{Question:}$

One of the angles of a triangle measures 80° and the other two angles are equal. Find the measure of each of the equal angles.

$\rm\bf\underline{Solution:}$

given angle 80

more two angles are equal then

total angle in triangle is 180

then X,X,80 are angles

so X+X+80=180

2x +80=180

2x=180-80

2x=100

X =50

50,50,80are the angles

Answer 2

Answer: 50°

Explanation:

sum of all interior angles of a triangle= 180°

one of the angle=80°

let the other angle be x

there are two equal angles

2x+80°=180°

2x=180°-80°

2x=100°

x=100°/2

x=50°