one of the angles of a triangles measures 80°and the other two angles are equal find the measure of each of the equal angles please help me guys
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☆ Solution ☆
Given :-
- One of the angles of a triangles measures 80°and the other two angles are equal .
To Find :-
- The measure of each of the equal angles.
Step-by-Step-Explaination :-
As we know that :-
Sum of all angles of triangle is 180°
Let the second angle be x
And third angle be x
Then,
80° + x+ x = 180°
So,
2x = 180° - 80°
2x = 100
x = 100/2
x = 50
So,
Angles are 50°, 50° and 80°
Answered by
1
Answer:
lrl
Step-by-step explanation:
let X be the first angle
given that one angle=80
and 2nd angle=3rd angle
that means X=X
we know that sum of angles in triangle =180
so, X+X+80=180
2X=180
X=180/2=90
Hence, required angles are 80,90,90
I think this question is wrong because of sum of angles in triangle must be 180 but it is greater than 180
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