Question

one of the angles of parallelogram is 42 degree. what is the sum of half the smallest angle and twice the largedt angle of parallelogram​

Answer 1

Answer:

Let x∘ be the smallest angle of the parallelogram.

According to the question, the largest angle is (2x∘−24∘).

It is known that the sum of the adjacent angles of the parallelogram is 180∘. Then,

x∘+2x∘−24∘=180∘

3x∘=180∘+24∘

3x∘=204∘

x∘=68∘

Therefore, the largest angle is (2(68∘)−24∘)=112∘.

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Answer 2

Answer:

Require sum =( 2 * 138 + 42/2)

= 279 degrees