Question

One of the angles of the triangle is equal to the sum of the other two angles. If the

ratio of other two angles is 4:5, find measures of all angles of the triangle​

Answer 1

Answer:

Given ratio :- 4:5

Let it be 4x and 5x

Since

4x + 5x = 9x

There fore the third angle is equal to 9x

Then,

4x+5x+9x =180

18x=180

x=10

So the angle will be

First angle =4x

=40

Second angle=5x

=50

Third angle=9x

=90

Answer 2

Answer:

angles are 40 ,50 ,90

Step-by-step explanation:

let other two angles = 4k and 5k

third angle = 4k + 5k = 9k

A/Q

using angle sum property

9k +5k +4k =180

18k = 180

k = 10

putting k in angle measure

9k = 9(10) = 90

5k = 5(10) =  50

4k = 4(10) = 40