one of the diagonals of a rectangle is equal to one of its sides.find the angles of the rhombus
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Lets consider, ABCD is rhombus of sides AB=BC=CD=DA=AC diagonal of rhombus.
In triangle ΔBAC,
BA=BC=CA
∠BAC=∠ABC=∠ACB=60
0
. . . . . . . (1)
In triangle ΔADC
DA=DC=CA
∠BAC=∠ACD=∠ADC=60
0
. . . . . . . .(2)
From equation (1) and equation (2), we get
∠A=∠BAC+∠ADC
∠A=60
+60
=120
∠B=∠ABC=60
∠C=∠ACB+∠ACD=60
+60
=120
∠D=∠ADC=60
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