Question

One of the diagonals of a rhombus is thrice as
the other. If the sum of the length of the
diagonals is 24 cm, then find the area of the
rhombus.
​

Answer 1

Answer:

54cm²

Step-by-step explanation:

LET ONE BE x

OTHER BE 3x

ACCORDING TO THE QUESTION

x+3x=24

4x=24

x=6

ONE DIAGONAL=6cm

OTHER DIAGONAL =3×6=18cm

AREA OF A RHOMBUS = ½×d1×d2

(d1&d2 are the two diagonals of the rhombus)

=½×6×18

=54cm²

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