Question

One of the digits of a two digit number is five times the other.if we interchange the digits of this number and add the resulting number to the original number ,we get 66. What is the original number.

Answer 1

let number=10x+y

reverse the number=10y+X

According to the problem

X=5y

x-5y=0----(1)

10y+X+10x+y=66

(11x+11y=66)÷11

X+y=6-----(2)

from (1)and(2)

x-5y=0

X+y=6

(-)(-) (-)

sub -6y=-6

y=-6/-6

y=1

X=5y

X=5(1)

X=5

the number=10x+y

=10(5)+1

=50+1

=51

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