Physics, asked by archer54, 8 months ago

The fig. shows a man of mass 60kg standing
on a light weighing machine kept in a
box of mass 30kg. The box is hanging from a
pulley fixed to the ceiling through a light
rope, the other end which is held by the man
himself. If the man manages to keep the
bor at rest, what is the weight shown by
force should he exert to
the machine ? what
get his correct weight on the machine​

Answers

Answered by Aastha6878
4

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SOLUTION

Mass of men =60kg

Mass of box =30kg

Let R be the apparent height of men displayed on machine.

so,

R+T−60g=0 [from FBD of man]

T−R−30g=0 [from FBD of box]

comparing both,

R=15g

i.e wright shown an machine is 15kg.

Answered by Anonymous
8

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 \huge  \underline \bold{Answer : }

Mass of men =60kg

Mass of box =30kg

Let R be the apparent height of men displayed on machine.

so,

R+T−60g=0 [from FBD of man]

T−R−30g=0 [from FBD of box]

comparing both,

R=15g

i.e wright shown an machine is 15kg.

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