One of the equal sides of an Isosceles triangle is 13cm and its perimeter is 50cm, the area of the triangle
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Answer:
BC = 6 cm
Height AD = 4 cm
Area of ∆ = (1/2) base × height
= (1/2) × BC × AD
= (1/2) × 6 × 4 = 12 cm2
Again area of ∆ = (1/2) × AC × BE
12 = (1/2) × 8 × BE
∴ BE = (12 × 2)/8
BE = (12 × 2)/8
BE = 3 cm
∴ (i) 12cm2 (ii) 3 cm2
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