One of the exterior angle of a ∆ABC measures 150° . If one of the interior opposite angle is 75° . Find the other interior opposite angle . What type of triangle is this ?
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isoselus triangle is this because exterior angle be 150 -75=75 so, opposite angle be equal .so that isoleus triangle opposite side and angle be equal
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Let the exterior angle of ABC = 150°
One of the interior opposite angle= 75°
Let the other opposite interior angle be 'x'
Therefore,
=) x+75=150
=) x=150-75
=) x=75°
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One of the interior opposite angle= 75°
Let the other opposite interior angle be 'x'
Therefore,
=) x+75=150
=) x=150-75
=) x=75°
I hope that my answer will help u.
Plz like it and give it the brainliest answer if u r satisfied from the answer. Thank you!!!
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