one of the exterior angles of a triangle is 80 degrees and the interior opposite angles are in the ratio 3 :5 . find the angles of the triangle
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Answered by
194
Exterior angle = sum of interior opposite angles
let the interior angles be 3x and 5x
80=3x+5x
80=8x
x= 10
the angles are 30,50
the other angle is 180-(30+50) = 100
let the interior angles be 3x and 5x
80=3x+5x
80=8x
x= 10
the angles are 30,50
the other angle is 180-(30+50) = 100
Answered by
139
Exterior angle = 80 degree
Let on interior angle=3x
other interior angle =5x
3x+5x=80
8x=80
x=10 degree
first angle=30 degree
2nd angle = 50 degree
3rd angle=100 degree
Let on interior angle=3x
other interior angle =5x
3x+5x=80
8x=80
x=10 degree
first angle=30 degree
2nd angle = 50 degree
3rd angle=100 degree
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