Question

One of the exterior angles of a triangle is 80 dgree and the interior opposite angle are in the ratio 5:3. Find the angles of the triangle

Answer 1

Answer:

Step-by-step explanation:let interior angles be 5x and 3x.

Exterior angle=80°

So in triangle

Exterior angle =Sum of interior angles

80°=5x+3x

80°=8x

80÷8=x

x=10

So the interior angles are:-

5x=5×10=50.

3x=3×10=30.

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Answer 2

Answer:

let angle acd be an ext.angle of triangle abc

Step-by-step explanation:

angle acd =80°

5x + 3x=80

8x= 80° or x = 80° \ 8 =10

now,angle a =3×10=30

angle b=5×10=50°

also, angle acb+ 80=180°

angle acb =180 °-80 100°

the angle of the triangle are 30° ,50° and 100°