One of the exteroir angles of a triangle is 100*. The interior opposite angles are equal to each other. Find the measure of these equal interior opposite angles.
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Let the equal angles be x
Exterior angle = sum of interior opposite angles
100=x+x
100=2x
100/2=x
50=x
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Sum of interior and exterior angles = 180 degrees
If exterior angle = 100 degrees
Then,sum of interior angles = 180-100 = 80 degrees
As per the question, interior opposite angles are equal..
Linear equation for the same
= 2x = 80 (where x is each interior angle)
x = 80÷2
x = 40 degrees
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