Question

principal= Rs 1000 , rate =10% , time=3 years ..........

Answer 1

GIVEN :-

• Principal (P) = Rs. 1000
• Rate (R) = Rs. 10% p.a
• Time (T) = 3 years

TO FIND :-

• Simple interest (S.I)
• Amount (A) .

SOLUTION :-

❂ S.I = (P × R × T)/100

⇒ (1000 × 10 × 3)/100

⇒ 10 × 10 × 3

⇒ 100 × 3

⇒ 300

Hence Simple interest (S.I) is Rs. 300.

❂ Amount (A) = P + S.I

⇒ 1000 + 300

⇒ 1300

Hence Amount (A) is Rs.1300

VERIFICATION :-

⇒ S.I = A - P

⇒ 300 = 1300 - 100

⇒ 300 = 300

L.H.S = R.H.S

HENCE VERIFIED

Answer 2

$\huge \underline{ \underline{ \blue{given : }}}$

$\huge principal : 1000$

$\huge intrest \: : \: 10\%$

$\huge time \: : \: 3 \: years$

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$\huge \boxed{ \red{s.i \: : \: \frac{PRT}{100} }}$

$\huge \: \frac{1000 \times 10 \times 3}{100}$

$\huge \frac{10 \times 10 \times 3}{1}$

$\huge100 \times 3$

$\huge \boxed{ \boxed{\purple{S.I = 300}}}$

$\huge \green{ - - - - - - - }$

$\huge \orange{principle : 1000 }$

$\huge \orange{intrest \: : \: 300 }$

Sum of Principle+interest:

$\huge \red{ = 1000 + 300}$

$\huge \boxed { \boxed{\purple{ Amount= 1300}}}$

$\huge \green{ - - - - - - - }$

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Verification :-

S.I : Amount - Principle

300 = 1300 - 1000

300 = 300

hence verified

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Note:-

✏ P : Principle

✏ R : Rate of intrest

✏ T : Time

✏ A : Amount

✏ S.I: Simple Intrest

✏ $\huge { S.I \: : \: \frac{PRT}{100} }$

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