one of the factor of 2(b square-a square+2ac-c square)
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Solution:
2( b² - a² + 2ac - c² )
= 2[ b² - ( a² - 2ac + c² ) ]
= 2[ b² - ( a - c )² ]
[ Since , x² -2xy + y² = ( x - y )²]
= 2[ b + ( a - c )][ b - ( a - c )]
_______________________
By algebraic identity :
x² - y² = ( x + y )( x - y )
______________________
= 2( b + a - c )( b - a + c )
•••••••
2( b² - a² + 2ac - c² )
= 2[ b² - ( a² - 2ac + c² ) ]
= 2[ b² - ( a - c )² ]
[ Since , x² -2xy + y² = ( x - y )²]
= 2[ b + ( a - c )][ b - ( a - c )]
_______________________
By algebraic identity :
x² - y² = ( x + y )( x - y )
______________________
= 2( b + a - c )( b - a + c )
•••••••
sharpgroupofsis:
option nahi hai
didi
2 , ( b + a - c ), ( b - a + c ) are three factors
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