Question

One of the factors of (1 + 7x)² + (49x² – 1) is: *​

Answer 1

Answer:

The factors of the (1+7x)² + (49x²-1) are 7x+1 and 14x.

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Answer 2

Answer:

$(1 + 7x)^2$ + $(49x^{2}-1)$

Expanding $(1+7x)^2$

=> 1 + 49$x^{2}$ + 14$x$ + 49$x^{2}$ - 1

=> 98$x^{2}$ + 14$x$

Taking 14$x$ as common

$14x(7x+1)$

Therefore, the factors are 14$x$ and $7x+1$ .