one of the factors of (5x 2 + 70x – 160) is (x – 2). Find the other factor.
Answers
Answered by
30
Answer: we have to verify with zero
So x-2=0
Step-by-step explanation:
Attachments:
Answered by
10
Given,
The polynomial: 5x²+70x-160
One of its factors is (x-2).
To find,
The second factor of the given polynomial.
Solution,
The second factor of 5x²+70x-160 will be (x+16).
According to the question,
p(x) = 5x²+70x-160
5x²+70x-160 = 0
Taking 5 as common,
5(x²+14x-32) = 0
(x²+14x-32) = 0
Factorising it by splitting the middle term such that their subtraction will give 14x and multiplication will give 32x²:
x²+16x-2x-32 = 0
Taking x common from the first two terms and -2 from the last two terms:
x(x+16)-2(x+16) = 0
(x+16)(x-2) = 0
(x-2) is given as one of the factors.
Hence, the second factor of 5x²+70x-160 is (x+16).
Similar questions