Question

One of the factors of 5x^3+6x^2-5x-6 is x-1 ( TRUE or FALSE )

Answer 1

Answer:

True

Step-by-step explanation:

x-1 =0

x = 1

Now,Put the value in polynomial:-

=> 5×1³+6×1²-5×1-6 = 0

=> 5+6-5-6

=> 11-11 = 0.

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Answer 2

$\huge\sf\pink{Answer}$

☞ x-1 is a factor

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$\huge\sf\blue{Given}$

✭ p(x) = 5x³+6x²-5x-6

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$\huge\sf\gray{To \:Find}$

◈ If x-1 is a factor of the above Polynomial

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$\huge\sf\purple{Steps}$

So here we shall first equate x-1 with 0

➝ $\sf x-1 = 0$

➝ $\sf x = 1$

Substituting this in p(x) is,

➳ $\sf p(-1) = 5(-1)^3+6(-1)^2-5(-1)-6$

➳ $\sf 5(-1)+6(1)+5-6$

➳ $\sf -5+6+5-6$

➳ $\sf 11-11$

➳ $\sf 0$

$\sf \therefore$ x-1 is a factor of the polynomial 5x³+6x²-5x-6

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