Math, asked by virenderdhanda8470, 1 year ago

One of the parallel sides of a trapezium is double the other and it's height is 24cm . If area of the trapezium is 360cm find the length of the parallel sides,

Answers

Answered by ujjwalpandeygenius
0

1st parallel side =10 and longer side =30 cm

Answered by Anonymous
0

Given :

One of the parallel sides of trapezium is double the other

Height of the trapezium = 24 cm

Area of trapezium = 360 cm²

To Find :

The length of parallel sides of trapezium

Solution :

Let length of one of the parallel sides be "x" then the length of the other side becomes "2x".

Area of trapezium is given by ,

 \\  \star{\boxed{\purple{\sf{Area =  \frac{1}{2} \times (a + b) \times h }}}} \\  \\

here ,

a and b are lengths of parallel sides

h is height of trapezium

Subatituting the values we have in the formula ,

 \\   : \implies \sf \: 360 =  \frac{1}{2} \times (x  +  2x) \times 24 \\  \\

 \\   : \implies \sf \: 360 =  \frac{1}{2}  \times 3 {x}  \times 24 \\  \\

 \\  :  \implies \sf \:  3{x}^{}  \times 12 = 360 \\  \\

 \\   : \implies \sf \:  {x}^{}  =  \frac{360}{36}  \\  \\

 \\   : \implies{\underline{\boxed {\pink{\mathfrak{x =10  }}}}} \:\bigstar\\  \\

Now ,

Length of one of the parallel side (x) = 10 cm

Then ,

The length of the other parallel side (2x) = 2(10) = 20 cm

Hence ,

Lengths of the parallel sides of given trapezium are 10 cm and 20 cm

Answered by Anonymous
0

Given :

One of the parallel sides of trapezium is double the other

Height of the trapezium = 24 cm

Area of trapezium = 360 cm²

To Find :

The length of parallel sides of trapezium

Solution :

Let length of one of the parallel sides be "x" then the length of the other side becomes "2x".

Area of trapezium is given by ,

 \\  \star{\boxed{\purple{\sf{Area =  \frac{1}{2} \times (a + b) \times h }}}} \\  \\

here ,

a and b are lengths of parallel sides

h is height of trapezium

Subatituting the values we have in the formula ,

 \\   : \implies \sf \: 360 =  \frac{1}{2} \times (x  +  2x) \times 24 \\  \\

 \\   : \implies \sf \: 360 =  \frac{1}{2}  \times 3 {x}  \times 24 \\  \\

 \\  :  \implies \sf \:  3{x}^{}  \times 12 = 360 \\  \\

 \\   : \implies \sf \:  {x}^{}  =  \frac{360}{36}  \\  \\

 \\   : \implies{\underline{\boxed {\pink{\mathfrak{x =10  }}}}} \:\bigstar\\  \\

Now ,

Length of one of the parallel side (x) = 10 cm

Then ,

The length of the other parallel side (2x) = 2(10) = 20 cm

Hence ,

Lengths of the parallel sides of given trapezium are 10 cm and 20 cm

Answered by Anonymous
0

Given :

One of the parallel sides of trapezium is double the other

Height of the trapezium = 24 cm

Area of trapezium = 360 cm²

To Find :

The length of parallel sides of trapezium

Solution :

Let length of one of the parallel sides be "x" then the length of the other side becomes "2x".

Area of trapezium is given by ,

 \\  \star{\boxed{\purple{\sf{Area =  \frac{1}{2} \times (a + b) \times h }}}} \\  \\

here ,

a and b are lengths of parallel sides

h is height of trapezium

Subatituting the values we have in the formula ,

 \\   : \implies \sf \: 360 =  \frac{1}{2} \times (x  +  2x) \times 24 \\  \\

 \\   : \implies \sf \: 360 =  \frac{1}{2}  \times 3 {x}  \times 24 \\  \\

 \\  :  \implies \sf \:  3{x}^{}  \times 12 = 360 \\  \\

 \\   : \implies \sf \:  {x}^{}  =  \frac{360}{36}  \\  \\

 \\   : \implies{\underline{\boxed {\pink{\mathfrak{x =10  }}}}} \:\bigstar\\  \\

Now ,

Length of one of the parallel side (x) = 10 cm

Then ,

The length of the other parallel side (2x) = 2(10) = 20 cm

Hence ,

Lengths of the parallel sides of given trapezium are 10 cm and 20 cm

Answered by Anonymous
0

Given :

One of the parallel sides of trapezium is double the other

Height of the trapezium = 24 cm

Area of trapezium = 360 cm²

To Find :

The length of parallel sides of trapezium

Solution :

Let length of one of the parallel sides be "x" then the length of the other side becomes "2x".

Area of trapezium is given by ,

 \\  \star{\boxed{\purple{\sf{Area =  \frac{1}{2} \times (a + b) \times h }}}} \\  \\

here ,

a and b are lengths of parallel sides

h is height of trapezium

Subatituting the values we have in the formula ,

 \\   : \implies \sf \: 360 =  \frac{1}{2} \times (x  +  2x) \times 24 \\  \\

 \\   : \implies \sf \: 360 =  \frac{1}{2}  \times 3 {x}  \times 24 \\  \\

 \\  :  \implies \sf \:  3{x}^{}  \times 12 = 360 \\  \\

 \\   : \implies \sf \:  {x}^{}  =  \frac{360}{36}  \\  \\

 \\   : \implies{\underline{\boxed {\pink{\mathfrak{x =10  }}}}} \:\bigstar\\  \\

Now ,

Length of one of the parallel side (x) = 10 cm

Then ,

The length of the other parallel side (2x) = 2(10) = 20 cm

Hence ,

Lengths of the parallel sides of given trapezium are 10 cm and 20 cm

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