Question

one of the perpendicular sides of a right angled triangle has 4cm more than twice of other side. It has area 80 cm square. find out lenghts of perpendicular sides​

Answer 1

let one side = x

=> 4 cm more than 2x => 2x+4

=> x(2x+4)=80

=> x(x+2)=40

=> x² + 2x - 40 = 0

=> x = -2 ± √(2²+4*40) / 2

=> x = (-2 ± √1+40)

=> x = -2 ± √41

=> x = -2 ± 6.4

=> x = -2 + 6.4 or -2-6.4

=> x = 4.4 or -8.4

but length not in negative.

so that x =4.4

=> second length = 2*4.4 + 4 = 8.8+4 = 12.8

Answer 2

Answer:

$x(x + 2) = 80 \times 2x - 80 = 0x \\ = 2 - 2 + - 4 + 4(80)x = 1 + - 81x = - 1 + - 9x = 8or - 10 \: \\ but \: length \: this \: not - ve \: sides \: are \: 8 \: and \: 20 \: and \: 429$