Question

one of the rectangular components of a force of 40n is 20n . find the angle it makes with this component.

Answer 1

let this be the x component of the force,

F = 40 N
fx = 20 N

Let the angle between F and fx be Ф

F cosФ = fx
40 cosФ = 20

cos Ф = 1/2

Ф =  60°

Answer 2

It makes an angle of 60°, with the given component  

Given:

The forces of the rectangular component.  

To find:

We have to find the angle which it makes with it

Solution:

Let x be the component of the force which makes an angle \phi

From the given statement we have

F = 40 N

fx = 20 N

Let the angle between F and fx be $\phi$

$F \cos \phi=f x$

Substituting the values of f and fx we get

$40 \cos \phi=20$

$\cos \phi=\frac{20}{40}$

$\cos \phi=\frac{1}{2}$

To find the angle$\phi$ we shift cos to the right hand side

So we get

$\phi=\cos ^{-1} \frac{1}{2}$

$\phi=60^{\circ}$

Hence the angle made by the rectangular component is 60°.