Question

One of the root of a quadratic equation is
(3-
$\sqrt{2}$
), then which of the following is that
equation : INTSE-2015 (Stage-I) Maharashtra
(A) (x2-6r-7)=0 (B) (r2+ 6x - 7) = 0
(C) (r+6r+7)=0 (D) (r2 - 6x + 7) = 0​

Answer 1

Answer:

option A) is your answer hope it helps u

Answer 2

Answer:

a) 33. 4/6x? - 13x - 2/6 = 0 34

1 1 11

La

A7)

$4 \sqrt{6x2 - 13x - 2 \sqrt{6 = 0} }$