Question

one of the roots of equation x²+mx-5=0is 1.find on
a) 4
b)-4
c) 1
------
4
d)- 1
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4​

Answer 1

Answer:

d is the answer

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Answer 2

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Answer:

The value of m is 4.

Step-by-step explanation:

$equation \div {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

$\alpha = 1 \: \: \: \: \: \beta =$

${x}^{2} + mx - 5 = 0$

$\alpha + \beta = - m \: \: \: \: \: \: \alpha \beta = - 5$

$\beta = - m - 1 \: \: \: \: \: \: \beta = - 5$

$- m - 1 = - 5$

$m = 4$