Math, asked by memonsalma656, 6 months ago

one of the roots of quadratic equation kx2-3x-1=0 is 1/2 .solve the following to find value of k​

Answers

Answered by Flaunt
41

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

Given :

One of the roots of the quadratic equation k {x}^{2}  - 3x - 1 = 0 is 1/2

To Find:-

To find out the value of 'k'

_____________________________________________

If 1/2 is the root of the given Equation then it will satisfy the Equation :-

 =  > k {( \frac{1}{2}) }^{2}  - 3( \frac{1}{2} ) - 1

 =  >  \frac{k}{4}  -  \frac{3}{2}  - 1

 =  >  \frac{k - 6}{4}  - 1

 =  >  \frac{k - 6 - 4}{4}  = 0

 =  >  \frac{k - 10}{4}  = 0

 =  > k - 10 = 0

\bold{\pink{k = 10}}

Now,let's check k's value whether it satisfies the Equation or not

 =  > 10 {( \frac{1}{2} )}^{2}  - 3( \frac{1}{2} ) - 1

 =  >  \frac{10}{4}  -  \frac{3}{2}  - 1

 =  >  \frac{5}{2}  -  \frac{3}{2}  - 1

 =  >  \frac{5 - 3}{2}  - 1 =  \frac{2}{2}  - 1 = 1 - 1 = 0

Therefore,k satisfies the equation

Therefore,k satisfies the equation So, k value is 10

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