Question

One of the roots of quadratic equation x² - 2√3x + k = 0 is √3 , find k.​

Answer 1

Answer:

3

Step-by-step explanation:

given the root of the equation x² - 2√3x + k = 0 is √3

so by substituting it in the equation

$(\sqrt{3} )^{2} -2\sqrt{3}\sqrt{3}+K=0$

3-2(3)+K=0

3-6+k=0

-3+k=0

k=3