Question

one of the roots of the quadratic equations 6x²-x-2=0is

Answer 1

hey there!!

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${6x}^{2} - x - 2 = 0 \\ \\ 2x(3x - 2) + 1(3x - 2) = 0\\ \\ (2x + 1)(3x - 2) = 0$


so, roots of the eqn are x=2/3, -1/2
Thanks