Question

one of the roots of the quadritic equation a²x²-3abx + 2b²=0 is a)-2b/b b) -2a/b c) 2b/a d)2a/5​

Answer 1

Answer:

$c) \: \frac{2b}{a}$

Step-by-step explanation:

${a}^{2} {x}^{2} - 3abx + 2 {b}^{2} = 0$

${a}^{2} {x}^{2} - 2abx - abx + 2 {b}^{2} = 0$

$ax(ax - 2b) - b(ax - 2b) = 0$

$(ax - 2b)(ax - b) = 0$

$ax = b \: or \: 2b$

$x = \frac{b}{a} \: or \: \frac{2b}{a}$