Question

One of the satellites of Jupiter, has an orbital period of 1.769 days and radius of the orbit is 4.22 x 10^8 m ..Show that the mass of Jupiter is about one-thousandth that of the sun​

Answer 1

Explanation:

Hope this helps you......

Answer 2

Answer:

Given

Orbital period (T) =1.769 days

=1.769 × 24 × 3600

= 1.528 × 10^5 s

Radius of orbit (r) = 4.22×10^8m

Mass of the sun (Ms) =2×10^30kg

Let mass of Jupiter's satellite is m. and mass of Jupiter is Mj Centripetal force=Gravitational force

mv²/r= GMjm/r²

v²= GMj/r

we know,

v=wr and w =2π/The

so, v= 2πr/T [use this here,

Mj=4×(3.14)²×(4.22×10^8)³/(1.528×10^5)²×6.67×10^-11

=1.9×10^27kg≈ 2×10^27 kg

Mj/Ms=2×10^27/2×10^30=1/1000

Mj =Ms/1000

Hence, the mass of Jupiter is about one thousandth that sun.

$<marquee>THANKS❤</marquee>$