One of the solutions of ax+by =2 is 1] (1,2-b/a) 2] (2-b/0) 3] (2-b/a,1) 4] (0,2/a)
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One of the solutions of ax+by =2 is 1] (1,2-b/a) 2] (2-b/0) 3] (2-b/a,1) 4] (0,2/a)
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One of the solutions of ax+by =2 is 1] (1,2-b/a) 2] (2-b/0) 3] (2-b/a,1) 4] (0,2/a)Draw the graph of the lines 2x + y = 6 and 2x – y + 2 = 0 and find the area bounded by
these lines and x-axis.Probability (anaemic) =0.05
Probability (malnourishedgiven anaemic) = 0.5
Using Bayes rule gives:
Prob (anaemic given malnourished)
prob(anaemic) prob(manourished given anaemic)
prob(malnourished)
5 solution???Probability (anaemic) =0.05
Probability (malnourishedgiven anaemic) = 0.5
Using Bayes rule gives:
Prob (anaemic given malnourished)
prob(anaemic) prob(manourished given anaemic)
prob(malnourished)
5 solution???
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