one of the two circles touches the other internally. if their radii are 7cm and 4 cm find the distance between their centres.
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Hello Mate!
Given : Radii of two circles who touch each other internally has radii of 7 cm and 4 cm.
To find : Length of AB.
Solution : This means that, length of
BC = 4 cm and AC = 7 cm.
Now we know that,
AC - BC = AB
Hence, 7 cm - 4 cm = AB
3 cm = AB.
Hence length of distance between centers if two circles is 3 cm.
Have great future ahead!
Given : Radii of two circles who touch each other internally has radii of 7 cm and 4 cm.
To find : Length of AB.
Solution : This means that, length of
BC = 4 cm and AC = 7 cm.
Now we know that,
AC - BC = AB
Hence, 7 cm - 4 cm = AB
3 cm = AB.
Hence length of distance between centers if two circles is 3 cm.
Have great future ahead!
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As two circles touch each other internally
that means they have common tangent at P
So normal at p will pass through both the centers.
So Radii of bigger circle = AP = 7cm
Radii of smaller circle = BP = 4 cm
As distance between centres is AP -BP
So 7 -4 = 3 cm
So distance between centres is 3cm.
✌✌✌Dhruv✌✌✌✌
that means they have common tangent at P
So normal at p will pass through both the centers.
So Radii of bigger circle = AP = 7cm
Radii of smaller circle = BP = 4 cm
As distance between centres is AP -BP
So 7 -4 = 3 cm
So distance between centres is 3cm.
✌✌✌Dhruv✌✌✌✌
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